1. Concept Overview / Statement of the Law
An equipotential surface is a surface on which the electric potential is the same at every point.
This means:
- No work is required to move a charge anywhere along an equipotential surface.
- Electric field is always perpendicular to an equipotential surface.
- Equipotential surfaces show how potential varies in space without having to calculate it at every point.
Equipotential surfaces help students visualize:
- Where the region of high/low potential is,
- How electric field strength changes,
- How charges interact in space,
- How potential drops in circuits and physical systems.
Just like contour lines on a map represent equal height, equipotential surfaces represent equal electric potential.
2. Clear Explanation and Mathematical Treatment
Definition
A surface is said to be equipotential if:
[
V = \text{constant}
]
on all points of that surface.
Work Done Along Equipotential
Work done in moving a charge [q] from point A to B:
[
W = q(V_B – V_A)
]
If A and B lie on the same equipotential surface:
[
V_A = V_B \Rightarrow W = 0
]
Relation with Electric Field
Electric field is related to potential by:
[
\vec{E} = -\nabla V
]
This implies:
- Electric field lines point from higher potential to lower potential.
- Electric field is perpendicular to equipotential surfaces.
Examples of Equipotential Surfaces
| Charge Distribution | Nature of Equipotential Surfaces |
|---|---|
| Single point charge | Concentric spheres |
| Infinite line charge | Cylindrical surfaces |
| Infinite plane sheet | Parallel planes |
| Dipole | Complicated but symmetric 3D surfaces |
3. Dimensions and Units
Potential is measured in:
- SI Unit: Volt (V)
- Dimensions:
[[M L^2 T^{-3} A^{-1}]]
(Electric field and surface shape have no direct dimensions here.)
4. Key Features
- Potential is constant at all points on an equipotential surface.
- No work is done moving a charge along it.
- Electric field is always perpendicular to equipotential surfaces.
- Equipotential surfaces can never intersect.
- Where equipotential surfaces are close together, electric field is strong.
- Shape depends on the type of charge distribution.
- Equipotential surfaces provide intuitive visualization of the electric field pattern.
- Equipotentials around point charges are spherical; around dipoles are complex.
5. Important Formulas to Remember
| Concept | Formula |
|---|---|
| Work done | [W] [= q(V_B – V_A)] |
| No work along equipotential | [V_A] [= V_B \Rightarrow W = 0] |
| Relation with field | [\vec{E} = -\nabla V] |
| Field is normal to equipotential | [\vec{E} \cdot d\vec{l}_{\text{equipotential}}] [= 0] |
| Equipotentials around point charge | Spheres of radius r |
6. Conceptual Questions With Solutions
1. Why is no work done in moving a charge along an equipotential surface?
Because potential difference between any two points is zero: [V_A = V_B]. So [W = q(V_B – V_A) = 0].
2. Why are equipotential surfaces always perpendicular to electric field lines?
If they weren’t perpendicular, there would be a component of field along the surface, causing work. But work must be zero along equipotential surfaces.
3. Can two equipotential surfaces intersect?
No. If they intersected, a point would have two different potentials—impossible.
4. Why do equipotential surfaces around a point charge form spheres?
Because potential depends only on radial distance [r], not direction.
5. Why are equipotential surfaces closer in regions of stronger electric field?
Because steep potential change means surfaces occur at smaller intervals → strong field.
6. Are equipotential surfaces always real physical surfaces?
No. They are imaginary geometrical surfaces used only for understanding fields.
7. Can equipotential surfaces be flat?
Yes—example: Infinite plane sheet of charge.
8. How does a dipole’s equipotential surface differ from a single charge?
They are not spherical; they bend heavily due to opposite charges.
9. Why does electric field never lie along an equipotential surface?
Because that would produce potential change and hence work.
10. Is it possible for equipotential surfaces to be concentric cylinders?
Yes—around infinite line charges.
11. On the equatorial line of a dipole, why is potential zero?
Contributions from +q and –q cancel exactly because of symmetry.
12. If no charge is inside a region, can equipotential surfaces still exist?
Yes. They depend on the surrounding distribution of charges.
13. Why are equipotentials asymmetric for multiple charges?
Because the potential distribution becomes complex and direction-dependent.
14. If electric field is zero, what can we say about equipotential surfaces?
All surfaces overlap—potential is constant everywhere.
15. Why do conductors in electrostatic equilibrium form equipotential surfaces?
Charges rearrange until potential is the same everywhere on the conductor.
16. Is electric potential constant inside a hollow conducting sphere?
Yes, because electric field is zero inside.
7. FAQ / Common Misconceptions
1. “Equipotential surfaces exist physically like metal plates.”
No. They are imaginary surfaces for analysis.
2. “Electric field is zero on equipotential surfaces.”
Not true. Only the tangential component is zero.
3. “Equipotential surfaces can be drawn arbitrarily.”
No. They follow exactly from the charge distribution.
4. “Equipotentials around a dipole are spherical.”
False. Only a single charge gives spherical equipotentials.
5. “Equipotential surfaces must be evenly spaced.”
Spacing depends on electric field strength.
6. “If potentials are same at two points, electric field must be zero between them.”
No. Field depends on gradient, not equality at two points.
7. “Equipotential surfaces can intersect field lines.”
They can—but always at 90°.
8. “Equipotential surfaces around charged spheres depend on material.”
No. Shape depends only on symmetry, not material.
9. “No two charges can have overlapping equipotential surfaces.”
False. Equipotentials blend naturally for multiple charges.
10. “Zero potential means zero electric field.”
Incorrect. Potential can be zero while field is non-zero (e.g., dipole equatorial line).
8. Practice Questions (With Step-By-Step Solutions)
Q1.
What work is required to move a +2 μC charge along an equipotential surface of 10 V?
Solution:
Since it is an equipotential surface:
[
V_A = V_B
]
[
W = q(V_B – V_A) = 0
]
Answer: 0 J
Q2.
The potential difference between two equipotential surfaces is 5 V, and the distance between them is 2 mm.
Find electric field magnitude.
Solution:
[
E = -\dfrac{dV}{dr}
]
Given:
[dV] [= 5 \text{V} [,\quad] [dr = 2\times10^{-3} \text{ m}]
[E] [= \dfrac{5}{2\times10^{-3}}] [= 2500 \text{V/m}]
Q3.
A point charge q = 6 μC creates equipotential surfaces at 20 V, 30 V, 40 V… etc.
Find the distance between 20 V and 30 V surfaces.
Solution:
Potential due to point charge:
[
V = \dfrac{1}{4\pi\varepsilon_0} \dfrac{q}{r}
]
Thus:
[
r = \dfrac{9\times 10^9 \times 6\times10^{-6}}{V}
]
For 20 V:
[r_1] [= \dfrac{54\times10^{3}}{20}] [= 2700 \text{ m}]
For 30 V:
[r_2] [= \dfrac{54\times10^{3}}{30}] [= 1800 \text{ m}]
Distance:
[
\Delta r = 900 \text{ m}
]
Q4.
Why must electric field be perpendicular to equipotential surfaces? Show mathematically.
Solution:
Work done:
[
dW = \vec{E}\cdot d\vec{l}
]
But along equipotential:
[
dW = 0
]
Thus:
[
\vec{E}\cdot d\vec{l} = 0
]
Meaning:
[
\vec{E} \perp d\vec{l}
]
Q5.
For a dipole, equipotential surfaces are zero on equatorial line. Explain using formula.
Solution:
Dipole potential:
[V] [= \dfrac{1}{4\pi\varepsilon_0}\dfrac{p\cos\theta}{r^2}]
On equatorial line:
[
\theta = 90^\circ \Rightarrow \cos\theta = 0
]
Thus:
[
V = 0
]